Yoshio Takahashi

About the Kd approach to treat sorbing solutes, it is written that we must convert the unit of Kd from cm3/g to mol/g. Could you please explain how we can do that? In the textbook of the online academy (https://academy.gwb.com/sorbing_solutes.php), for example, the Kd for Pb2+ was given as 0.16 cm3/g, which was converted to 0.0003 mol/g. I would like to know details of the conversion, when we assume that (i) dissolved Pb2+ is 10 micromolar, (ii) the activity coefficient of Pb2+ in the goundwater is 0.66, and (iii) the free Pb2+ proportion is 80% of total dissolved Pb, as written in the textbook.