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tiziano

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  1. Let me illustrate it by assigning activity_Na+ = 0.2 and activity_K+ = 0.3. Considering the logarithm of the ratio, we have: log K = log[(0.2*1)/(0.3*0.891)] = -0.126. Considering the relationship log K = log(0.2)+0+0.05012-log(0.3) = -0.126. On the contrary, if we consider the relationship log K = LOG(0.2)+0-0.05012-LOG(0.3) = -0.226; i.e., we get a different number if we have -0.0512.

  2. Hi Jia, thank you for the quick answer.

    I still have a doubt, because taking your formulation:

    logK = log activity(K-feldspar) + log activity(Na+) - log activity(albite) - log activity(K+)

    then it would be

    logK = log activity(1) + log activity(Na+) - log activity(0.891) - log activity(K+)

    logK = 0 + log activity (Na+) − (−0.05012) - log activity (K+)

    So:

    log⁡(K)= log ⁡activity(Na+) + 0.05012 − log ⁡activity(K+))

    In other words, there should be +0.05012 because we have -(-0.05012).

    Thank you

     

  3. Dear GWB users,

    I have noticed something weird in the RXN tool. Specifically, writing the reaction:

    albite_low + K+ = k-feldspar + Na+

    and assigning an activity of 0.891 to k-feldspar, the logK is calculated as:

    logK = -0.0501 + logNa - logK

    However, in reality, the logarithm of the equilibrium constant should be:

    logK = +0.05012 + logNa - logK

    because:

    logK = log[(Na/(K*0.891)] = logNa - log(K*0.891) = logNa - logK - log(0.891) = logNa - logK + 0.0512

    Is that not correct? Or perhaps I am making a mistake somewhere? I would like to specify that I am using version 12.0.9.

    2024-01-10 22_00_30-Window.png

    2024-01-10 22_00_56-Window.png

  4. Hi, I am using GWB 12.0.6. These are the results obtained by Spec8:

              Temperature =  13.9 C    Pressure =  1.013 bars
              pH =  7.997
              Ionic strength      =    0.005059 molal
              Charge imbalance    =   -0.000267 eq/kg (-3.873% error)
              Activity of water   =    0.999995
              Solvent mass        =      1.0000 kg
              Solution mass       =      1.0003 kg
              Mineral mass        =     0.00000 kg
              Solution density    =    1.021    g/cm3
              Solution viscosity  =    0.012    poise
              Chlorinity          =    0.000132 molal
              Dissolved solids    =         291 mg/kg sol'n
              Elect. conductivity =      326.08 uS/cm (or umho/cm)
              Hardness            =      164.64 mg/kg sol'n as CaCO3
                carbonate         =      164.64 mg/kg sol'n as CaCO3
                non-carbonate     =        0.00 mg/kg sol'n as CaCO3
              Carbonate alkalinity=      172.96 mg/kg sol'n as CaCO3
              Water type          =    Ca-HCO3
              Bulk volume         =        980. cm3
              Fluid volume        =        980. cm3
              Mineral volume      =       0.000 cm3
              Inert volume        =       0.000 cm3
              Porosity            =        100. %
              Permeability        =        98.7 cm2

    Water is fresh (TDS = 291 mg/kg sol'n), so I am very surprised to obtain a calculated density of 1.021 g/cm3. This latter value is typical of seawater or an NaCl brine. Indeed, using PHREEQC and density calculation by Pizer.dat dataset, I have obtained Density (g/cm³)  =   0.99950.
    Thank you.

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