tiziano
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Posts posted by tiziano
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Let me illustrate it by assigning activity_Na+ = 0.2 and activity_K+ = 0.3. Considering the logarithm of the ratio, we have: log K = log[(0.2*1)/(0.3*0.891)] = -0.126. Considering the relationship log K = log(0.2)+0+0.05012-log(0.3) = -0.126. On the contrary, if we consider the relationship log K = LOG(0.2)+0-0.05012-LOG(0.3) = -0.226; i.e., we get a different number if we have -0.0512.
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Hi Jia, thank you for the quick answer.
I still have a doubt, because taking your formulation:
logK = log activity(K-feldspar) + log activity(Na+) - log activity(albite) - log activity(K+)
then it would be
logK = log activity(1) + log activity(Na+) - log activity(0.891) - log activity(K+)
logK = 0 + log activity (Na+) − (−0.05012) - log activity (K+)
So:
log(K)= log activity(Na+) + 0.05012 − log activity(K+))
In other words, there should be +0.05012 because we have -(-0.05012).
Thank you
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Dear GWB users,
I have noticed something weird in the RXN tool. Specifically, writing the reaction:
albite_low + K+ = k-feldspar + Na+
and assigning an activity of 0.891 to k-feldspar, the logK is calculated as:
logK = -0.0501 + logNa - logK
However, in reality, the logarithm of the equilibrium constant should be:
logK = +0.05012 + logNa - logK
because:
logK = log[(Na/(K*0.891)] = logNa - log(K*0.891) = logNa - logK - log(0.891) = logNa - logK + 0.0512
Is that not correct? Or perhaps I am making a mistake somewhere? I would like to specify that I am using version 12.0.9.
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Hi, I am using GWB 12.0.6. These are the results obtained by Spec8:
Temperature = 13.9 C Pressure = 1.013 bars
pH = 7.997
Ionic strength = 0.005059 molal
Charge imbalance = -0.000267 eq/kg (-3.873% error)
Activity of water = 0.999995
Solvent mass = 1.0000 kg
Solution mass = 1.0003 kg
Mineral mass = 0.00000 kg
Solution density = 1.021 g/cm3
Solution viscosity = 0.012 poise
Chlorinity = 0.000132 molal
Dissolved solids = 291 mg/kg sol'n
Elect. conductivity = 326.08 uS/cm (or umho/cm)
Hardness = 164.64 mg/kg sol'n as CaCO3
carbonate = 164.64 mg/kg sol'n as CaCO3
non-carbonate = 0.00 mg/kg sol'n as CaCO3
Carbonate alkalinity= 172.96 mg/kg sol'n as CaCO3
Water type = Ca-HCO3
Bulk volume = 980. cm3
Fluid volume = 980. cm3
Mineral volume = 0.000 cm3
Inert volume = 0.000 cm3
Porosity = 100. %
Permeability = 98.7 cm2Water is fresh (TDS = 291 mg/kg sol'n), so I am very surprised to obtain a calculated density of 1.021 g/cm3. This latter value is typical of seawater or an NaCl brine. Indeed, using PHREEQC and density calculation by Pizer.dat dataset, I have obtained Density (g/cm³) = 0.99950.
Thank you.
something weird in Rxn logK
in Rxn, Act2 and Tact2
Posted
Oops, I realized that I was mistaken. I had assigned 1 to the k-feldspar activity instead of albite. Problem solved. I apologize for the false alarm! 🙂