lvsoar Posted October 6, 2009 Share Posted October 6, 2009 Hi, I have 3 basic questions about ACT2: (1) If I want to plot a ACT-ACT diagram on Cu, is that true that for the diagram species I can only input total activity instead of molality? I see that it only gives me the choice of activity or log activity. (2) If I input the total activity of 10^-3 for Cu, is the 10^-3 including both the dissolved and solid phases? (3) How is the boundary between aqueous species and solid phases defined in ACT2? Garrels and Christ, defined the boundary as the point where the “sum of the activities of the ions in equilibrium with the solid exceeds some chosen value”. They chose 10^-6 as a default value on the basis that if it is less than this value, the solid will tend to behave as an immobile constituent in the environment. My question is whether the boundary is defined following Garrels and Christ (boundary at total dissolved Cu to be 10^-6) or to be the line where mineral precipitation begins? Thanks, Peng Quote Link to comment Share on other sites More sharing options...
Tom Meuzelaar Posted October 12, 2009 Share Posted October 12, 2009 Hi, I have 3 basic questions about ACT2: Hi Peng: 1) Indeed, since this is an activity diagram, all species concentrations must be input as activities. 2) If you specify an activity for Cu++, you are constraining the non-ideal concentration (or activity) for the dissolved Cu++ species. 3) Any boundary in Act2 is simply the mass action equation between the species/minerals on either side of the boundary written in terms of the axis species. For example, on a Quartz solubility diagram with log SiO2 activity as the Y-axis and -log H+ activity (pH) as the X-axis, the boundary between dissolved silica and Quartz is expressed by the reaction: Quartz = SiO2(aq) Which has the mass action equation: K = aSiO2(aq) From the thermodynamic database, the log K value at 25C for this reaction is -3.9993. Substituting for K and aSiO2, and switching to log scale, we come up with the final equation as it's plotted in Act2: Y = -3.999 Note that since the reaction is only written in terms of the Y-axis (ie. not in terms of H+ activity), there is a Y-intercept, but no line slope- that is, the line plots as a horizontal line on the activity diagram. I hope this helps. Regards, Tom Meuzelaar RockWare, Inc. Quote Link to comment Share on other sites More sharing options...
lvsoar Posted October 15, 2009 Author Share Posted October 15, 2009 Hi Tom, Thanks for your reply. I have a follow up question on (3). If I set Cu activity in the system as 1e-6 and use "thermo" database to plot, how are the boundaries of CuOH+ vs Tenorite and CuOH+ vs Cuprite defined? Does the program assume the CuOH+ to be 1e-6 M when calculating the boundaries? Or, it will speciate Cu++ and CuOH+ at certain pH value and used the real activity of CuOH+ (say 1.5e-8 M) to calculate the boundaries? Peng Hi Peng: 1) Indeed, since this is an activity diagram, all species concentrations must be input as activities. 2) If you specify an activity for Cu++, you are constraining the non-ideal concentration (or activity) for the dissolved Cu++ species. 3) Any boundary in Act2 is simply the mass action equation between the species/minerals on either side of the boundary written in terms of the axis species. For example, on a Quartz solubility diagram with log SiO2 activity as the Y-axis and -log H+ activity (pH) as the X-axis, the boundary between dissolved silica and Quartz is expressed by the reaction: Quartz = SiO2(aq) Which has the mass action equation: K = aSiO2(aq) From the thermodynamic database, the log K value at 25C for this reaction is -3.9993. Substituting for K and aSiO2, and switching to log scale, we come up with the final equation as it's plotted in Act2: Y = -3.999 Note that since the reaction is only written in terms of the Y-axis (ie. not in terms of H+ activity), there is a Y-intercept, but no line slope- that is, the line plots as a horizontal line on the activity diagram. I hope this helps. Regards, Tom Meuzelaar RockWare, Inc. Quote Link to comment Share on other sites More sharing options...
Tom Meuzelaar Posted October 15, 2009 Share Posted October 15, 2009 Hi Tom, Thanks for your reply. I have a follow up question on (3). If I set Cu activity in the system as 1e-6 and use "thermo" database to plot, how are the boundaries of CuOH+ vs Tenorite and CuOH+ vs Cuprite defined? Does the program assume the CuOH+ to be 1e-6 M when calculating the boundaries? Or, it will speciate Cu++ and CuOH+ at certain pH value and used the real activity of CuOH+ (say 1.5e-8 M) to calculate the boundaries? Peng Hi Peng: You can look at the calculations behind an entire activity diagram by choosing the Run - View - .\Act2_output.txt menu option. I think this will answer all of your questions. Regards, Tom Quote Link to comment Share on other sites More sharing options...
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