Jump to content
Geochemist's Workbench Support Forum

Rate constant in "catalysis" example


Recommended Posts

Dear GWB Team,

I attended GWB workshop in 2020 where we were given the 'catalysis' code to simulate Mn(II) oxidation on Fe(OH)3. I had a few doubts regarding the same:

1. How did we get the rate constant = 20000 ? Was it from a paper or just a number chosen for showing the process?

2. Why did we not include activation energy? Is it combined in the above number?

3. Why was Fe(OH)3(ppd) used? Can other minerals be used? 

4. How did we get the surface area of Fe(OH)3?

5. Why MnO2 (aq) has the log k = 9?

Thank you!

Link to comment
Share on other sites

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Paste as plain text instead

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

Loading...
×
×
  • Create New...